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  1. Asked: April 16, 2021In: Arithmetic, Numbers and Combinatorics, High School/Senior Secondary School

    What does the Fibonacci sequence mean?

    acedstud
    acedstud
    Added an answer on April 16, 2021 at 7:46 am

    Fibonacci sequence is a sequence where each number is obtained by adding the two preceding numbers, starting from 0 and 1. That is, $T_n=T_{n-1}+T_{n-2}$, $T_1=0$, $T_2=1$.

    Fibonacci sequence is a sequence where each number is obtained by adding the two preceding numbers, starting from 0 and 1. That is, T_n=T_{n-1}+T_{n-2}, T_1=0, T_2=1.

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  2. Asked: April 16, 2021In: Calculus and Trigonometry, High School/Senior Secondary School

    Calculus assignment

    acedstud
    acedstud
    Added an answer on April 16, 2021 at 7:40 am

    The derivative of an implicit function, $x^2+y^2=9$ is $2x+2yy'=0\Rightarrow2yy'=-2x\Rightarrow y'=-\dfrac{x}{y}$ From, $x^2+y^2=9$, we have $y^2=9-x^2\Rightarrow y=\sqrt{9-x^2}$. Therefore, $y'=-\dfrac{x}{\sqrt{9-x^2}}$

    The derivative of an implicit function, x^2+y^2=9 is 2x+2yy'=0\Rightarrow2yy'=-2x\Rightarrow y'=-\dfrac{x}{y}

    From, x^2+y^2=9, we have y^2=9-x^2\Rightarrow y=\sqrt{9-x^2}.

    Therefore, y'=-\dfrac{x}{\sqrt{9-x^2}}

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  3. Asked: April 16, 2021In: Middle School/Junior Secondary School

    Science – Physics

    acedstud
    acedstud
    Added an answer on April 16, 2021 at 7:10 am

    The wavelength ($\lambda$) of a wave with speed, $v$, and frequency, $f$, is given by $\lambda=\dfrac{v}{f}$. Here, $v=12$ m/s and $f=0.25$ s, therefore, $\lambda=\dfrac{12}{0.25}=48$ m.

    The wavelength (\lambda) of a wave with speed, v, and frequency, f, is given by \lambda=\dfrac{v}{f}.

    Here, v=12 m/s and f=0.25 s, therefore, \lambda=\dfrac{12}{0.25}=48 m.

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  4. Asked: April 16, 2021In: Arithmetic, Numbers and Combinatorics, High School/Senior Secondary School

    Ordinary Annuity

    acedstud
    acedstud
    Added an answer on April 16, 2021 at 6:17 am

    The value of an annuity of $P$ peso paid $t$ times a year at a rate of $r$% compounded $t$ times a year for $n$ years is given by $FV=\dfrac{P\left(1+\frac{r}{t}\right)^{nt}}{\frac{r}{t}}$. Here, $p=10,000$, $t=12$ times a year (monthly), $r=9$% = 0.09, $n=5$ years. Thus, $FV=\dfrac{10000\left(1+\frRead more

    The value of an annuity of P peso paid t times a year at a rate of r% compounded t times a year for n years is given by FV=\dfrac{P\left(1+\frac{r}{t}\right)^{nt}}{\frac{r}{t}}.

    Here, p=10,000, t=12 times a year (monthly), r=9% = 0.09, n=5 years.

    Thus, FV=\dfrac{10000\left(1+\frac{0.09}{12}\right)^{5\times12}}{\frac{0.09}{12}}=\dfrac{10000(1.0075)^{60}}{0.0075}

    =\dfrac{15656.81027}{0.0075}=2,087,574.70 peso.

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  5. Asked: April 16, 2021In: Applied Mathematics, College/University

    Decimal to Binary Conversion

    acedstud
    acedstud
    Added an answer on April 16, 2021 at 6:02 am

    To convert a number to binary, we continuously divide the number by 2 and record the remainders. Thus, dividing 23 continuously by 2 gives 2 23 2 11 R 1 2 5 R 1 2 2 R 1 2 1 R 0 0 R 1 Reading the remainders from down up, we have that 23 to binary is 10111.

    To convert a number to binary, we continuously divide the number by 2 and record the remainders.

    Thus, dividing 23 continuously by 2 gives

    2 23
    2 11 R 1
    2 5 R 1
    2 2 R 1
    2 1 R 0
    0 R 1

    Reading the remainders from down up, we have that 23 to binary is 10111.

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  6. Asked: April 15, 2021In: College/University, Statistics and Probability

    what is one to one fuction?

    acedstud
    acedstud
    Added an answer on April 15, 2021 at 4:04 pm

    A function is said to be one-to-one if every element in the codomain is mapped to exactly one element in the domain. That is, no two elements in the domain map to one element in the codomain.

    A function is said to be one-to-one if every element in the codomain is mapped to exactly one element in the domain.

    That is, no two elements in the domain map to one element in the codomain.

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  7. Asked: April 15, 2021In: High School/Senior Secondary School

    If a x b = 2a – 3b + ab, then 3 x 5 + 5 x 3 is equal to?

    acedstud
    acedstud
    Added an answer on April 15, 2021 at 3:49 pm

    Let x be a binary operation such that a x b = 2a - 3b + ab, then 3 x 5 = 2(3) - 3(5) + (3)(5) = 6 - 15 + 15 = 6, and 5 x 3 = 2(5) - 3(3) + (5)(3) = 10 - 9 + 15 = 16. Therefore, 3 x 5 + 5 x 3 = 6 + 16 = 22.

    Let x be a binary operation such that a x b = 2a – 3b + ab, then 3 x 5 = 2(3) – 3(5) + (3)(5) = 6 – 15 + 15 = 6, and 5 x 3 = 2(5) – 3(3) + (5)(3) = 10 – 9 + 15 = 16.

    Therefore, 3 x 5 + 5 x 3 = 6 + 16 = 22.

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  8. Asked: April 14, 2021In: Algebra, High School/Senior Secondary School

    Permutation problem

    acedstud
    acedstud
    Added an answer on April 15, 2021 at 7:29 am

    Any of the 15 contestants can take the 1st position. Any of the remaining 14 contestants (after the first position is selected) can take the 2nd position. And any of the remaining 13 contestants can take the 3rd position. Therefore, the number of ways, the first, second, and third positions can be sRead more

    Any of the 15 contestants can take the 1st position. Any of the remaining 14 contestants (after the first position is selected) can take the 2nd position. And any of the remaining 13 contestants can take the 3rd position.

    Therefore, the number of ways, the first, second, and third positions can be selected is given by 15\times14\times13=2,730 ways.

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  9. Asked: April 15, 2021In: College/University, Statistics and Probability

    mathematics for everyone

    acedstud
    acedstud
    Added an answer on April 15, 2021 at 7:16 am

    The probability that the first student cannot solve the problem is $1-\dfrac{1}{2}=\dfrac{1}{2}$. The probability that the second student cannot solve the problem is $1-\dfrac{1}{3}=\dfrac{2}{3}$. The probability that the third student cannot solve the problem is $1-\dfrac{1}{4}=\dfrac{3}{4}$. The pRead more

    The probability that the first student cannot solve the problem is 1-\dfrac{1}{2}=\dfrac{1}{2}.

    The probability that the second student cannot solve the problem is 1-\dfrac{1}{3}=\dfrac{2}{3}.

    The probability that the third student cannot solve the problem is 1-\dfrac{1}{4}=\dfrac{3}{4}.

    The probability that none of the three students can solve the problem is \dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}=\dfrac{6}{24}=\dfrac{1}{4}.

    Thus, the probability that the problem is solved is 1-\dfrac{1}{4}=\dfrac{3}{4}.

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  10. Asked: April 15, 2021In: Calculus and Trigonometry, High School/Senior Secondary School

    Calculus and Trigonometry

    acedstud
    acedstud
    Added an answer on April 15, 2021 at 7:07 am

    To find the inverse of $f(x)=\ln(2x-3)+2$, first, for simplicity sake, let's substitute $y$ for $f(x)$ to get $y=\ln(2x-3)+2$. Next, subtract 2 from both sides to get $y-2=\ln(2x-3)$. Next, take the exponent of both sides to get $e^{y-2}=e^{\ln(2x-3)}=2x-3$. Next, add 3 to both sides to get $e^{y-2}Read more

    To find the inverse of f(x)=\ln(2x-3)+2, first, for simplicity sake, let’s substitute y for f(x) to get y=\ln(2x-3)+2.

    Next, subtract 2 from both sides to get y-2=\ln(2x-3).

    Next, take the exponent of both sides to get e^{y-2}=e^{\ln(2x-3)}=2x-3.

    Next, add 3 to both sides to get e^{y-2}+3=2x.

    Next, divide through by 2 to get \dfrac{1}{2}e^{y-2}+\dfrac{3}{2}=x\Rightarrow x=\dfrac{1}{2}e^{y-2}+\dfrac{3}{2}.

    Finally, we will substitute x for y and f^{-1}(x) for x to get f^{-1}(x)=\dfrac{1}{2}e^{x-2}+\dfrac{3}{2}

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