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a square tile measures
by 
. How many of such tiles will cover a floor measuring 
by 
?
floor area= $5\times 4=20m^{2}$ square tile area=$0.2\times 0.2=0.04m^{2}$ number of tiles that will cover the floor=$\dfrac{20}{0.04}=500$ tiles
floor area=
tiles
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number of tiles that will cover the floor=
The angle of a sector of a circle of radius
is 
. if 
, what is the perimeter of the sector?
Perimeter of sector=$2r + Length of arc$ Perimeter of sector=$2r + \dfrac{\theta }{360}\times 2\Pi r$ $\theta =150^{0},r=4.2cm, \Pi =\dfrac{22}{7}$ $\Rightarrow P=2\times 4.2+\dfrac{150}{360}\times 2\times \dfrac{22}{7} \times 4.2$ $\Rightarrow P=8.4 + 0.417\times 2 \times 3.142\times 4.2$ $\RightarRead more
Perimeter of sector=
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Solve
$\begin{vmatrix} 8 & 7\\ 16 & 11 \end{vmatrix}$ $\Rightarrow (8\times 11)-(7\times 16)$ $\Rightarrow 88-112=-24$
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$\begin{vmatrix} 4 & 1\\ 8 & 1 \end{vmatrix}$ $\Rightarrow (4\times 1)-(8\times 1)$ $\Rightarrow 4-8=-4$
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$\begin{vmatrix} 3 & 2\\ -3 & 6 \end{vmatrix}$ $\Rightarrow (6\times 3)-(-3\times 2)$ $\Rightarrow 18-(-6)=24$
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$\begin{vmatrix} 2 & 7\\ -1 & 3 \end{vmatrix}$ $\Rightarrow (2\times 3)-(-1\times 7)$ $\Rightarrow 6-(-7)=13$
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$\begin{vmatrix} 6 & -3\\ -3 & 7 \end{vmatrix}$ $\Rightarrow (6\times 7)-(-3\times -3)$ $\Rightarrow 42-9=33$
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$\begin{vmatrix} 0 & -1\\ -3 & 1 \end{vmatrix}$ $\Rightarrow (0\times 1)-(-3\times -1)$ $\Rightarrow 0-3=-3$
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$\begin{vmatrix} 9 & -3\\ 4 & 2 \end{vmatrix}$ $\Rightarrow (9\times 2)-(-3\times 4)$ $\Rightarrow 18-(-12)=30$
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