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  1. Asked: April 8, 2021In: Arithmetic, Numbers and Combinatorics, High School/Senior Secondary School

    What is the formula of Arithmetic sequence?

    Sengemegz
    Best Answer
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 5:25 am

    Arithmetic sequence $T_{n}= a+(n-1)d$ Where a= first term n= number of terms d= common difference

    Arithmetic sequence T_{n}= a+(n-1)d

    Where

    a= first term

    n= number of terms

    d= common difference

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  2. Asked: April 7, 2021In: Elementary School

    Multiplication Division Addition Subtraction

    Sengemegz
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 5:19 am

    $38 \times 12+4 -9 \div 2$ Applying BODMAS $38 \times 12+4- 4.5$ $456+4- 4.5$ $460-4.5$ $\rightarrow 455.5 =\dfrac{911}{2}$

    38 \times 12+4 -9 \div 2

    Applying BODMAS

    38 \times 12+4- 4.5

    456+4- 4.5

    460-4.5

    \rightarrow 455.5 =\dfrac{911}{2}

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  3. Asked: April 7, 2021In: High School/Senior Secondary School

    Mathematics module

    Sengemegz
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 5:03 am

    Sum of interior angles= $(2n-4) \times 90$ Where n= number of sides=$16$ Sum= $(2 \times 16 - 4) \times 90$ Sum =$(32-4) \times 90$ Sum= $28 \times 90$ Sum = $2520$

    Sum of interior angles= (2n-4) \times 90

    Where n= number of sides=16

    Sum= (2 \times 16 - 4) \times 90

    Sum =(32-4) \times 90

    Sum= 28 \times 90

    Sum = 2520

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  4. Asked: April 7, 2021In: Algebra, High School/Senior Secondary School

    If A = 2x – y + 3xy, B = x + 2xy and C = 3y + xy, find the value of A+B+C

    Sengemegz
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 4:56 am

    A=2x-y+3xy , B=x +2xy and C=3y+xy A+B+C= $2x-y+3xy+x+2xy+3y+xy$ Collect like terms $\rightarrow 2x+x-y+3y+3xy+2xy+xy$ $\rightarrow 3x+2y+6xy$

    A=2x-y+3xy , B=x +2xy and C=3y+xy

    A+B+C= 2x-y+3xy+x+2xy+3y+xy

    Collect like terms

    \rightarrow 2x+x-y+3y+3xy+2xy+xy

    \rightarrow 3x+2y+6xy

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  5. Asked: April 8, 2021In: Elementary School

    Science Titleeeee

    Sengemegz
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 4:49 am

    Static friction is the force an object at rest possesses. It is the maximum that must be overcome to move a body from rest.

    Static friction is the force an object at rest possesses. It is the maximum that must be overcome to move a body from rest.

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  6. Asked: March 30, 2021In: Geometry, High School/Senior Secondary School

    This is about Geometry

    Sengemegz
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 4:42 am

    Molecular geometry of 1)$CO_{2}$= tetrahedral 2) $SO_{2}$=Trigonal planar 3) $PF_{5}$= square pyramidal 4)$H_{2}O$=tetrahedral(bent)  

    Molecular geometry of

    1)CO_{2}= tetrahedral

    2) SO_{2}=Trigonal planar

    3) PF_{5}= square pyramidal

    4)H_{2}O=tetrahedral(bent)

     

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  7. Asked: April 6, 2021In: Geometry, High School/Senior Secondary School

    Geometry Problem solving

    Sengemegz
    Best Answer
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 4:25 am

    The perimeter of shape ABC( Triangle) = $l+l+l$ Perimeter= $8.5cm+8.5cm+(6+6)cm=29cm$

    The perimeter of shape ABC( Triangle) = l+l+l

    Perimeter= 8.5cm+8.5cm+(6+6)cm=29cm

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  8. Asked: March 30, 2021In: Middle School/Junior Secondary School

    Element can be extracted from seaweeds

    Sengemegz
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 4:21 am

    Iodine

    Iodine

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  9. Asked: March 30, 2021In: Middle School/Junior Secondary School

    Nutrient deficiency

    Sengemegz
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 4:18 am

    Iron and Sodium

    Iron and Sodium

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  10. Asked: April 8, 2021In: Middle School/Junior Secondary School

    Special right triangle

    Sengemegz
    Best Answer
    Sengemegz Moderator
    Added an answer on April 9, 2021 at 4:12 am

    Area of square= $l^{2}=121cm^{2}$ $\therefore l= \sqrt{121}= 11cm$ Diagonal= $\sqrt{11^{2}+11^{2}}$ Diagonal= $\sqrt{121+121}$ Diagonal= $\sqrt{242}=15.56cm$

    Area of square= l^{2}=121cm^{2}

    \therefore l= \sqrt{121}= 11cm

    Diagonal= \sqrt{11^{2}+11^{2}}

    Diagonal= \sqrt{121+121}

    Diagonal= \sqrt{242}=15.56cm

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