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  1. Asked: January 17, 2021In: Calculus and Trigonometry

    If y=\cos 3x, find \dfrac{d^{2}y}{dx^{2}}

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 2:23 pm

    $y=\cos 3x$ Let $u=3x$ and $y=\cos u$ $\dfrac{du}{dx}=3$ and $\dfrac{dy}{du}=-\sin u$ $\dfrac{dy}{dx}= \dfrac{du}{dx}\times \dfrac{dy}{du}$ $\dfrac{dy}{dx}= 3\times -\sin u$ $\dfrac{dy}{dx}= -3\sin u$ $\dfrac{dy}{dx}= -3\sin 3x$ $\dfrac{d^{2}y}{dx^{2}}= 3\times -3\cos 3x$ $\dfrac{d^{2}y}{dx^{2}}= -9Read more

    y=\cos 3x
    Let u=3x and y=\cos u
    \dfrac{du}{dx}=3 and \dfrac{dy}{du}=-\sin u
    \dfrac{dy}{dx}= \dfrac{du}{dx}\times \dfrac{dy}{du}
    \dfrac{dy}{dx}= 3\times -\sin u
    \dfrac{dy}{dx}= -3\sin u
    \dfrac{dy}{dx}= -3\sin 3x
    \dfrac{d^{2}y}{dx^{2}}= 3\times -3\cos 3x
    \dfrac{d^{2}y}{dx^{2}}= -9\cos 3x

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  2. Asked: January 17, 2021In: Calculus and Trigonometry

    If y=\cos 3x, find \dfrac{dy}{dx}

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 2:16 pm

    $y=\cos 3x$ Let $u=3x$ and $y=\cos u$ $\dfrac{du}{dx}=3$ and $\dfrac{dy}{du}=-\sin u$ $\dfrac{dy}{dx}= \dfrac{du}{dx}\times \dfrac{dy}{du}$ $\dfrac{dy}{dx}= 3\times -\sin u$ $\dfrac{dy}{dx}= -3\sin u$ $\dfrac{dy}{dx}= -3\sin 3x$

    y=\cos 3x
    Let u=3x and y=\cos u
    \dfrac{du}{dx}=3 and \dfrac{dy}{du}=-\sin u
    \dfrac{dy}{dx}= \dfrac{du}{dx}\times \dfrac{dy}{du}
    \dfrac{dy}{dx}= 3\times -\sin u
    \dfrac{dy}{dx}= -3\sin u
    \dfrac{dy}{dx}= -3\sin 3x

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  3. Asked: January 17, 2021In: Calculus and Trigonometry

    If y=3\cos 2x, find \dfrac{dy}{dx}

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 2:13 pm

    $y=3\cos 2x$ Let $u=2x$ and $y=3\cos u$ $\dfrac{du}{dx}=2$ and $\dfrac{dy}{du}=-3\sin u$ $\dfrac{dy}{dx}= \dfrac{du}{dx}\times \dfrac{dy}{du}$ $\dfrac{dy}{dx}= 2\times -3\sin u$ $\dfrac{dy}{dx}= -6\sin u$ $\dfrac{dy}{dx}= -6\sin 2x$

    y=3\cos 2x
    Let u=2x and y=3\cos u
    \dfrac{du}{dx}=2 and \dfrac{dy}{du}=-3\sin u
    \dfrac{dy}{dx}= \dfrac{du}{dx}\times \dfrac{dy}{du}
    \dfrac{dy}{dx}= 2\times -3\sin u
    \dfrac{dy}{dx}= -6\sin u
    \dfrac{dy}{dx}= -6\sin 2x

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  4. Asked: January 17, 2021In: Calculus and Trigonometry

    If y=3\cos x+3\sin x-\cos 2x, find \dfrac{dy}{dx}

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 12:19 pm

    $y=3\cos x+3\sin x-\cos 2x$ $\Rightarrow \dfrac{dy}{dx}=-3\sin x+3\cos x+2\sin 2x$

    y=3\cos x+3\sin x-\cos 2x
    \Rightarrow \dfrac{dy}{dx}=-3\sin x+3\cos x+2\sin 2x

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  5. Asked: January 17, 2021In: Calculus and Trigonometry

    If y=3\cos x+3\sin x-\cos 2x, find \dfrac{d^{2}y}{dx^{2}}

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 12:18 pm

    $y=3\cos x+3\sin x-\cos 2x$ $\Rightarrow \dfrac{dy}{dx}=-3\sin x+3\cos x+2\sin 2x$ $\Rightarrow \dfrac{d^{2}y}{dx^{2}}=-3\cos x-3\sin x+4\cos 2x$

    y=3\cos x+3\sin x-\cos 2x
    \Rightarrow \dfrac{dy}{dx}=-3\sin x+3\cos x+2\sin 2x
    \Rightarrow \dfrac{d^{2}y}{dx^{2}}=-3\cos x-3\sin x+4\cos 2x

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  6. Asked: January 17, 2021In: Calculus and Trigonometry

    If y=\tan 2x, find \dfrac{dy}{dx}

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 12:13 pm

    $y=\tan 2x$ Let $u=2x$ and $y=\tan u$ $\Rightarrow \dfrac{du}{dx}=2$ and $\dfrac{dy}{du}=\sec^{2}x$ $\Rightarrow \dfrac{dy}{dx}=\dfrac{du}{dx}\times \dfrac{dy}{du}$ $\Rightarrow \dfrac{dy}{dx}=2\times \sec^{2}x$ $\Rightarrow \dfrac{dy}{dx}=2\sec^{2}x$

    y=\tan 2x
    Let u=2x and y=\tan u
    \Rightarrow \dfrac{du}{dx}=2 and \dfrac{dy}{du}=\sec^{2}x
    \Rightarrow \dfrac{dy}{dx}=\dfrac{du}{dx}\times \dfrac{dy}{du}
    \Rightarrow \dfrac{dy}{dx}=2\times \sec^{2}x
    \Rightarrow \dfrac{dy}{dx}=2\sec^{2}x

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  7. Asked: January 17, 2021In: Calculus and Trigonometry

    Using quotient rule, find \dfrac{dy}{dx} if y=\dfrac{\sin x}{1+\cos x}

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 12:05 pm
    This answer was edited.

    Let $u=\sin x$ and $v=1+\cos x$ $\Rightarrow \dfrac{du}{dx}=\cos x$ and $\dfrac{dv}{dx}=-\sin x$ $\Rightarrow \dfrac{dy}{dx}=\dfrac{v\dfrac{du}{dx}-u\dfrac{dv}{dx}}{v^{2}}$ $\Rightarrow \dfrac{dy}{dx}=\dfrac{(1+\cos x)^{2}\times \cos x-\sin x\times -\sin x}{(1+\cos x)^{2}}$ $\Rightarrow \dfrac{dy}{dRead more

    Let u=\sin x and v=1+\cos x

    \Rightarrow \dfrac{du}{dx}=\cos x and \dfrac{dv}{dx}=-\sin x

    \Rightarrow \dfrac{dy}{dx}=\dfrac{v\dfrac{du}{dx}-u\dfrac{dv}{dx}}{v^{2}}

    \Rightarrow \dfrac{dy}{dx}=\dfrac{(1+\cos x)^{2}\times \cos x-\sin x\times -\sin x}{(1+\cos x)^{2}}

    \Rightarrow \dfrac{dy}{dx}=\dfrac{(1+2\cos x+\cos ^{2}x)\times \cos x+\sin^{2}x}{(1+\cos x)^{2}}

    \Rightarrow \dfrac{dy}{dx}=\dfrac{\cos x+2\cos ^{2}x+\cos ^{3}x+\sin^{2}x}{(1+\cos x)^{2}}

    from trig. identities \sin ^{2}x=1-\cos ^{2}x

    \Rightarrow \dfrac{dy}{dx}=\dfrac{\cos x+2\cos ^{2}x+\cos ^{3}x+1-\cos^{2}x}{(1+\cos x)^{2}}

    \Rightarrow \dfrac{dy}{dx}=\dfrac{\cos x+\cos ^{2}x+\cos ^{3}x+1}{(1+\cos x)^{2}}

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  8. Asked: January 17, 2021In: Calculus and Trigonometry

    Find \dfrac{dy}{dx} if y=x^{2}\cos 2x

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 11:41 am
    This answer was edited.

    $y=x^{2}\cos 2x$ Let $u=x^{2}$ and $v=\cos 2x$ $\Rightarrow \dfrac{du}{dx}=2x$ and $\dfrac{dv}{dx}=-2\sin 2x$ $\Rightarrow \dfrac{dy}{dx}=v\dfrac{du}{dx}+u\dfrac{dv}{dx}$ $\Rightarrow \dfrac{dy}{dx}=\cos 2x\times 2x+x^{2}\times -2\sin 2x$ $\Rightarrow \dfrac{dy}{dx}=2x\cos 2x-2x^{2}\sin 2x$ $\RightaRead more

    y=x^{2}\cos 2x
    Let u=x^{2} and v=\cos 2x
    \Rightarrow \dfrac{du}{dx}=2x and \dfrac{dv}{dx}=-2\sin 2x
    \Rightarrow \dfrac{dy}{dx}=v\dfrac{du}{dx}+u\dfrac{dv}{dx}
    \Rightarrow \dfrac{dy}{dx}=\cos 2x\times 2x+x^{2}\times -2\sin 2x
    \Rightarrow \dfrac{dy}{dx}=2x\cos 2x-2x^{2}\sin 2x
    \Rightarrow \dfrac{dy}{dx}=2x(\cos 2x-x\sin 2x)

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  9. Asked: January 17, 2021In: Calculus and Trigonometry

    Find \dfrac{dy}{dx} if y=3\cos x-\sin x

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 11:12 am

    $y=3\cos x-\sin x$ $\Rightarrow \dfrac{dy}{dx}=-3\sin x-\cos x$

    y=3\cos x-\sin x
    \Rightarrow \dfrac{dy}{dx}=-3\sin x-\cos x

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  10. Asked: January 17, 2021In: Calculus and Trigonometry

    If y=x^{3}-3x^{2}+6x=1, find \dfrac{dy}{dx}

    Sengemegz
    Sengemegz Moderator
    Added an answer on January 25, 2021 at 10:58 am

    $y=x^{3}-3x^{2}+6x-1$ $\Rightarrow \dfrac{dy}{dx}=3\times x^{3-1}-2\times 3x^{2-1}+6$ $\Rightarrow \dfrac{dy}{dx}=3x^{2}-6x+6$

    y=x^{3}-3x^{2}+6x-1
    \Rightarrow \dfrac{dy}{dx}=3\times x^{3-1}-2\times 3x^{2-1}+6
    \Rightarrow \dfrac{dy}{dx}=3x^{2}-6x+6

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