Center at (4,5), tangent to the y-axis

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_cinnamonrollTyro

Asked: March 30, 20212021-03-30T03:26:42+00:00 2021-03-30T03:26:42+00:00In: Middle School/Junior Secondary School

Center at (4,5), tangent to the y-axis

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Find the standard equation of the circle described

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acedstud · Answer 1 · 2021-03-30T08:38:05+00:00

acedstud

2021-03-30T08:38:05+00:00Added an answer on March 30, 2021 at 8:38 am

The equation of a circle with a center at $(h, k)$ and radius, $r$ , is given by $(x-h)^2+(y-k)^2=r^2$ .

Here, the center is at (4, 5) so $h=4$ and $k=5$ . Since the circle is tangent to the $y$ -axis, the radius is the length from the center (4, 5) to the $y$ -axis, which is 4. Thus, $r=4$ .

Therefore, the required equation is $(x-4)^2+(y-5)^2=4^2$ .

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Center at (4,5), tangent to the y-axis

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