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courage
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Tyro
Asked: 2020-11-27T20:08:27+00:00 In:

Find the value of \cos 540^{0}

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Find the value of \cos 540^{0}

trigonometry-angles greater than 360

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  2. Sengemegz
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    \cos 540^{0}
    first step is to subtract 360 from the value above
    \Rightarrow \cos (540^{0}-360^{0})=\cos 180^{0}
    180 falls in the second quadrant and cosine is negative
    \Rightarrow -\cos (180^{0}-180^{0})=-\cos 0^{0}
    using table
    \therefore -\cos 0^{0}=-1

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