1. 9x-81=0
2. 5x+2=27
3. 5(x+2)=3(x+10)
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1.) Given:![Rendered by QuickLaTeX.com 9x-81=0](https://acedstudy.com/wp-content/ql-cache/quicklatex.com-298febe249eee4cfd22fa9804f624683_l3.png)
Adding 81 to both sides, we have
.
Dividing both sides by the coefficient of
, which is 9, we have
.
Therefore,
.
2.) Given:![Rendered by QuickLaTeX.com 5x+2=27](https://acedstudy.com/wp-content/ql-cache/quicklatex.com-20c9e96563227d25dc44277e7f6d9009_l3.png)
Subtracting 2 from both sides, we have
.
Dividing both sides by the coefficient of
, which is 5, we have
.
Therefore,
.
c.) Given:![Rendered by QuickLaTeX.com 5(x+2)=3(x+10)](https://acedstudy.com/wp-content/ql-cache/quicklatex.com-06916904b42cb2faef3588d7357e0bef_l3.png)
Using foil/distributive law to expand, we have
.
Subtracting
from both sides gives
.
Subtracting 10 from both sides gives
.
Dividing both sides by 2 gives
.
Therefore,
.