Solve $x^{2}+3x-5=0$

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godwin_ibrahimTyro

Asked: November 20, 20202020-11-20T20:08:53+00:00 2020-11-20T20:08:53+00:00In: Algebra

Solve $x^{2}+3x-5=0$

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Solve $x^{2}+3x-5=0$

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Sengemegz · Accepted Answer · 2020-12-16T20:52:54+00:00

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Sengemegz Moderator

2020-12-16T20:52:54+00:00Added an answer on December 16, 2020 at 8:52 pm

$x^{2}+3x-5=0$
$a=1, b=3, c=-5$
using formula method
$x=\dfrac{-b\pm \sqrt{b^{2}-4ac}}{2a}$
$x=\dfrac{-(3)\pm \sqrt{(3)^{2}-4(1)(-5)}}{2\times 1}$
$x=\dfrac{-3\pm \sqrt{9+20}}{2}$
$x=\dfrac{-3\pm \sqrt{29}}{2}$
$x=\dfrac{-3\pm 5.385}{2}$
$\therefore$ either $x=\dfrac{-3+ 5.385}{2}=1.1925$
or $x=\dfrac{-3- 5.385}{2}=-4.1925$

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