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Tyro
Asked: 2020-12-20T14:34:14+00:00 In:

The angle of a sector of a circle of radius 4.2cm is 150^{0}. if \Pi =\dfrac{22}{7}, what is the perimeter of the sector?

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The angle of a sector of a circle of radius 4.2cm is 150^{0}. if \Pi =\dfrac{22}{7}, what is the perimeter of the sector?

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2 Answers

  2. Sengemegz
    Moderator
    This answer was edited.

    Perimeter of sector=2r + Length of arc
    Perimeter of sector=2r + \dfrac{\theta }{360}\times 2\Pi r
    \theta =150^{0},r=4.2cm, \Pi =\dfrac{22}{7}
    \Rightarrow P=2\times 4.2+\dfrac{150}{360}\times 2\times \dfrac{22}{7} \times 4.2\Rightarrow P=8.4 + 0.417\times 2 \times 3.142\times 4.2\Rightarrow P=8.4 + 11.0058\therefore P=19.4058cm$

  4. Odinaka_O
    Best Answer
    Tyro

    Perimeter of sector=2r + Length of arc
    Perimeter of sector=2r + \dfrac{\theta }{360}\times 2\Pi r
    \theta =150^{0},r=4.2cm, \Pi =\dfrac{22}{7}
    \Rightarrow P=2\times 4.2+\dfrac{150}{360}\times 2\times \dfrac{22}{7} \times 4.2
    \Rightarrow P=8.4 + 0.417\times 2 \times 3.142\times 4.2
    \Rightarrow P=8.4 + 11.0058
    \therefore P=19.4058cm

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