Find its 9th term and the sum of the last 12 terms of the sequence.

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This answer was edited.The nth term of an arithmetic sequence is given by , where is the first term and is the common difference.

Given: , .

The 9th term is given by .

The sum of the first n terms of an arithmetic sequence is given by .

The sum of the

first12 terms is given by .This answer was edited.## First term of the sequence is 10 and common difference is 5.

a1 = -4 and d = 5

Next term = a2=a1+d=-4+5=1

a3=a2+d=1+5=6

## a4=6+5=11

## a5=11+5=16

## a6=16+5=21

## a7=21+5=27

a8=27+5= 32

a9=32+5=37

a10=37+5=42

a11=42+5=47

a12=47+5=52

_{an=a1+(n−1)d}So 9th term is 37

sum of 12 th term is 288