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  1. Asked: March 28, 2021In:

    Slope of a Function

    qoraj
    qoraj Junior

    The function $f(x)=x$.

    The function f(x)=x.

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  2. Asked: March 14, 2021In: ,

    Question of the Day (14/03/2021)

    qoraj
    qoraj Junior
    This answer was edited.

    We know that the equation of a tangent line of the curve on a function $f$ at the point  $A$ with abscissa $x_0$  is $y=f'(x_0)(x-x_0)+f(x_0)$, in our case $x_0=-1$, so the equation is $y=f'(-1)(x-(-1))+f(-1)$ $y=f'(-1)(x+1)+f(-1)$ So let's calculate  $f'(-1)$ and $f(-1)$. We have Thus $f'(x)= -3 -Read more

    We know that the equation of a tangent line of the curve on a function f at the point  A with abscissa x_0  is y=f'(x_0)(x-x_0)+f(x_0), in our case x_0=-1, so the equation is y=f'(-1)(x-(-1))+f(-1)

    y=f'(-1)(x+1)+f(-1)

    So let’s calculate  f'(-1) and f(-1).

    We have f(x)=-3x-x^4

    Thus f'(x)= -3 - 4x^3

    Then f'(-1)=-3 - 4(-1)^3 = -3-4(-1)=-3+4=1

    And f(-1)= -3(-1) - (-1)^4 =3 -1=2

    Therefore y=1(x+1)+2

    Finaly y=x + 3

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