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Write the equation of the line with
$m=\dfrac{8}{3}; x_{1}=0;y_{1}=5$ $y-y_{1}=m(x-x_{1})$ $y-5=\dfrac{8}{3}(x-0)$ $y-5=\dfrac{8}{3}(x)$ open up the bracket $y-5=\dfrac{8}{3}x$ Add $5$ to both sides $y=\dfrac{8}{3}x+5$





to both sides

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Add
Write the equation of the line with
$m=-\dfrac{7}{6}; x_{1}=0;y_{1}=-3$ $y-y_{1}=m(x-x_{1})$ $y--3=-\dfrac{7}{6}(x-0)$ $y+3=-\dfrac{7}{6}(x)$ open up the bracket $y+3=-\dfrac{7}{6}x$ Subtract $3$ from both sides $y=-\dfrac{7}{6}x-3$ $y=-\dfrac{7}{6}x-3$





from both sides


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Subtract
Write the equation of the line with
$m=4; x_{1}=1;y_{1}=3$ $y-y_{1}=m(x-x_{1})$ $y-3=4(x-1)$ $y-3=4(x-1)$ open up the bracket $y-3=4x-4$ Add $3$ to both sides $y=4x-4+3$ $y=4x-1$





to both sides


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Add
Write the equation of the line with
$m=3; x_{1}=2;y_{1}=7$ $y-y_{1}=m(x-x_{1})$ $y-7=3(x-2)$ $y-7=3(x-2)$ open up the bracket $y-7=3x-6$ Add $7$ to both sides $y=3x-6+7$ $y=3x+1$





to both sides


See lessopen up the bracket
Add
Write the equation of the line with
$m=4; x_{1}=2;y_{1}=7$ $y-y_{1}=m(x-x_{1})$ $y-7=4(x-2)$ $y-7=4(x-2)$ open up the bracket $y-7=4x-8$ Add $7$ to both sides $y=4x-8+7$ $y=4x-1$





to both sides


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Add
Write the equation of the line with
$m=3; x_{1}=5;y_{1}=2$ $y-y_{1}=m(x-x_{1})$ $y-2=3(x-5)$ $y-2=3(x-5)$ open up the bracket $y-2=3x-15$ Add $2$ to both sides $y=3x-15+2$ $y=3x-13$





to both sides


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Add
Write the equation of the line with
$m=7; x_{1}=6;y_{1}=1$ $y-y_{1}=m(x-x_{1})$ $y-1=7(x-6)$ $y-1=7(x-6)$ open up the bracket $y-1=7x-42$ Add $1$ to both sides $y=7x-42+1$ $y=7x-41$





to both sides


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Add
Write the equation of the line with
$m=3; x_{1}=5;y_{1}=2$ $y-y_{1}=m(x-x_{1})$ $y-2=3(x-5)$ $y-2=3(x-5)$ open up the bracket $y-2=3x-15$ Add $2$ to both sides $y=3x-15+2$ $y=3x-13$





to both sides


See lessopen up the bracket
Add
Write the equation of the line with
$m=6; x_{1}=2;y_{1}=5$ $y-y_{1}=m(x-x_{1})$ $y-5=6(x-2)$ $y-5=6(x-2)$ open up the bracket $y-5=6x-12$ Add $5$ to both sides $y=6x-12+5$ $y=6x-7$





to both sides


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Add
Write the equation of the line with
$m=2; x_{1}=1;y_{1}=3$ $y-y_{1}=m(x-x_{1})$ $y-3=2(x-1)$ $y-3=2(x-1)$ open up the bracket $y-3=2x-2$ Add $3$ to both sides $y=2x-2+3$ $y=2x+1$





to both sides


See lessopen up the bracket
Add