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Find the derivative of
$y=3+x-x^{2}$ $\dfrac{dy}{dx}=0+1\times x^{1-1}-2\times x^{2-1}$ $\dfrac{dy}{dx}=0+x^{0}-2x^{1}$ $\dfrac{dy}{dx}=1-2x$
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$y=x^{3}+x^{2}-1$ $\dfrac{dy}{dx}=3\times x^{3-1}+2\times x^{2-1}-1$ $\dfrac{dy}{dx}=3x^{2}+2x^{1}-0$ $\dfrac{dy}{dx}=3x^{2}+2x$
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$y=2x^{2}$ $\dfrac{dy}{dx}=2\times 2x^{2-1}$ $\dfrac{dy}{dx}=4x^{1}$ $\dfrac{dy}{dx}=4x$
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$y=4x^{3}-3x$ $\dfrac{dy}{dx}=3\times 4x^{3-1}-1\times 3x^{1-1}$ $\dfrac{dy}{dx}=12x^{2}-3x^{0}$ $\dfrac{dy}{dx}=12x^{2}-3$
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$y=4x^{3}-3x^{2}$ $\dfrac{dy}{dx}=3\times 4x^{3-1}-2\times 3x^{2-1}$ $\dfrac{dy}{dx}=12x^{2}-6x^{1}$ $\dfrac{dy}{dx}=12x^{2}-6x$
See lessGiven
, find 
$y=6x^{2}-1$ $\dfrac{dy}{dx}=2\times 6x^{2-1}-0$ $\dfrac{dy}{dx}=12x^{1}+0$ $\dfrac{dy}{dx}=12x$
See lessGiven
, find 
$y=4x^{3}$ $\dfrac{dy}{dx}=3\times 4x^{3-1}$ $\dfrac{dy}{dx}=12x^{2}+0$ $\dfrac{dy}{dx}=12x^{2}$
See lessGiven
, find 
$y=\dfrac{1}{2}x^{2}+1$ $\dfrac{dy}{dx}=2\times \dfrac{1}{2}x^{2-1}+0$ $\dfrac{dy}{dx}=x^{1}+0$ $\dfrac{dy}{dx}=x$
See lessGiven
, find 
$y=x^{2}-x$ $\dfrac{dy}{dx}=1\times x^{2-1}-1\times x^{1-1}$ $\dfrac{dy}{dx}=x^{1}-x^{0}$ $\dfrac{dy}{dx}=x-1$
See lessGiven
, find 
$y=2x^{2}+3$ $\dfrac{dy}{dx}=2\times 2x^{2-1}+0$ $\dfrac{dy}{dx}=4x^{1}+0$ $\dfrac{dy}{dx}=4x$
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