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Find the value of
$\tan 600^{0}$ first step is to subtract 360 from the value above $\tan (600^{0}-360^{0})= \tan 240^{0}$ 240 falls in the second quadrant and tangent is positive $\Rightarrow +\tan (240^{0}-180^{0})=\tan 60^{0}$ using table $\therefore \tan 60^{0}=1.732$
See lessfirst step is to subtract 360 from the value above
240 falls in the second quadrant and tangent is positive
using table
Find the value of
$\tan 480^{0}$ first step is to subtract 360 from the value above $\tan (480^{0}-360^{0})= \tan 120^{0}$ 120 falls in the second quadrant and tangent is negative $-\tan (180^{0}-120^{0})=-\tan 60^{0}$ using table $\therefore -\tan 60^{0}=-1.732$
See lessfirst step is to subtract 360 from the value above
120 falls in the second quadrant and tangent is negative
using table
Find the value of
$\cos 540^{0}$ first step is to subtract 360 from the value above $\Rightarrow \cos (540^{0}-360^{0})=\cos 180^{0}$ 180 falls in the second quadrant and cosine is negative $\Rightarrow -\cos (180^{0}-180^{0})=-\cos 0^{0}$ using table $\therefore -\cos 0^{0}=-1$
See lessfirst step is to subtract 360 from the value above
180 falls in the second quadrant and cosine is negative
using table
Find the value of
$\sin 540^{0}$ since 540 is bigger than 360, we will subtract 360 from 540 $\sin (540^{0}-360^{0})=\sin (180^{0})$ 180 falls in the second quadrant and sine is positive $+\sin (180^{0}-180^{0})=\sin 0^{0}$ $\therefore \sin 0^{0}=0$
See lesssince 540 is bigger than 360, we will subtract 360 from 540
180 falls in the second quadrant and sine is positive
Find the value of
$\cos (-210^{0})=-\cos (210^{0})$ since 210 falls in the third quadrant and cosine is positive $\Rightarrow -(+\cos (210^{0}-180^{0}))$ using table $\therefore -\cos (30^{0})=-0.866$
See lesssince 210 falls in the third quadrant and cosine is positive
using table
Find the value of
$\tan (-120^{0})=-\tan (120^{0})$ since 120 falls in the second quadrant and tangent is negative $\Rightarrow -(-\tan (180^{0}-120^{0}))$ using four figure table $\therefore \tan 60^{0}=1.732$
See lesssince 120 falls in the second quadrant and tangent is negative
using four figure table
Find the value of
$\sin (-30^{0})=-\sin (30^{0})$ 30 falls on the first quadrant and sine is positive $\therefore -\sin 30^{0}=-0.5$
See less30 falls on the first quadrant and sine is positive
Find the value of
$\tan (-40^{0})=-(\tan40^{0})$ since 40 falls in the first quadrant and tangent is positive $\Rightarrow -(+\tan40^{0})$ using four figure table $\therefore -\tan40^{0}=-0.8391$
See lesssince 40 falls in the first quadrant and tangent is positive
using four figure table
Find the value of
$\sin (-150^{0})=- \sin (150^{0})$ since 150 falls in the second quadrant and sine is positive $-(+\sin (180^{0}-150^{0}))=-(\sin 30^{0})$ using four figure table $\therefore -(\sin 30^{0})=-0.5$
See lesssince 150 falls in the second quadrant and sine is positive
using four figure table
Find the value of
$\cos (-60^{0})=-\cos (60^{0})$ using four figure table $-\cos (60^{0})= -0.5$ or $-\dfrac{1}{2}$
or 
See lessusing four figure table