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matcha
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Tyro
Asked: 2021-04-21T09:31:04+00:00 In: ,

Applied Mathematics: Kinematics

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A ball is dropped from the top of the tower, 56m high. how long does it take to hit ground? at what speed is it then travelling?

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  2. acedstud

    The relationship between the vertical height, h, the time, t, the initial velocity, u, and the acceleration due to gravity, g, is given by h=ut+\dfrac{1}{2}gt^2.

    Here, h=56 m, u=0, g=9.8 m/s^2.

    Thus, 56=0\times t+\dfrac{1}{2}9.8t^2\Rightarrow56=4.9t^2\Rightarrow t^2=\dfrac{56}{4.9}=11.42857143

    \Rightarrow t=\sqrt{11.42857143}\approx3.38 seconds.

    Using, v=u+gt, we have v=0+9.8\times3.38=33.13 m/s.

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