Find the value of $x$ , between $0^{0}$ and $360^{0}$ , for which: $\tan x=-1.125$

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godwin_ibrahimTyro

Asked: November 25, 20202020-11-25T19:31:41+00:00 2020-11-25T19:31:41+00:00In: Calculus and Trigonometry

Find the value of $x$ , between $0^{0}$ and $360^{0}$ , for which: $\tan x=-1.125$

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Find the value of $x$ , between $0^{0}$ and $360^{0}$ , for which: $\tan x=-1.125$

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Sengemegz · Accepted Answer · 2020-12-07T12:38:38+00:00

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Sengemegz Moderator

2020-12-07T12:38:38+00:00Added an answer on December 7, 2020 at 12:38 pm

$\tan x=-1.125$
$\tan x$ is negative in the 2nd and 4th quadrants
from tables, $\therefore x=48.37^{0}$
$\Rightarrow (180-48.37)^{0}=131.63^{0}$
$\Rightarrow (360-48.37)^{0}=311.63^{0}$
$\therefore x=131.63^{0}$ or $311.63^{0}$

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