To provide the best experiences, we use technologies like cookies to store and/or access device information. Consenting to these technologies will allow us to process data such as browsing behavior or unique IDs on this site. Not consenting or withdrawing consent, may adversely affect certain features and functions.

Functional
Always active

The technical storage or access is strictly necessary for the legitimate purpose of enabling the use of a specific service explicitly requested by the subscriber or user, or for the sole purpose of carrying out the transmission of a communication over an electronic communications network.

Preferences

The technical storage or access is necessary for the legitimate purpose of storing preferences that are not requested by the subscriber or user.

Statistics

The technical storage or access that is used exclusively for statistical purposes.The technical storage or access that is used exclusively for anonymous statistical purposes. Without a subpoena, voluntary compliance on the part of your Internet Service Provider, or additional records from a third party, information stored or retrieved for this purpose alone cannot usually be used to identify you.

Marketing

The technical storage or access is required to create user profiles to send advertising, or to track the user on a website or across several websites for similar marketing purposes.

This answer was edited.7-8.Let,μ= ∑[x · P(X)]be your formula finding the Mean.y · P(Y)0o.630.5We multiplied

so, the products arey and P(Y)0, 0.63, 0.5Then, we will just

summate0, 0.63, o.5to find the.Mean0 + 0.63 + o.5

=1.13Therefore, the Mean is

μ= 1.13To find the

Variance. Let,σ^{2}= ∑[x^{2}· P(X)]- μ^{2 }be your formula finding the Variance.y^{2}y^{2}· P(Y)0010.6341[0 + 0.63 + 1]- 1.13

^{2}= 0.35Therefore, the Variance is

σ^{2}= 0.359-10.Let,μ= ∑[x · P(X)]be your formula finding the Mean.z · P(Z)0.230.90.960.23 + 0.9 + 0.96= 2.09

Therefore, the Mean is

μ= 2.09To find the

Variance. Let,σ^{2}= ∑[x^{2}· P(X)]- μ^{2 }be your formula finding the Variance.z^{2}z^{2}· P(Z)10.2341.892.88[0.23 + 1.8 + 2.88]- 2.09

^{2}= 0. 54Therefore, the Variance is

σ^{2}= 0.54