There are 4 red balls, 2 white balls and 5 blue balls in a box.
a. What are the possible order of 3 balls drawn at a time could be made?
b. How many possible order of 4 balls drawn at a time could be made with 2 red balls and 1 blue ball?
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There are 4 red balls, 2 white balls and 5 blue balls in a box.
a. What are the possible order of 3 balls drawn at a time could be made?
b. How many possible order of 4 balls drawn at a time could be made with 2 red balls and 1 blue ball?
Let R represent red, W represents white, and b represents blue, then
a.) The possible order of 3 balls drawn at a time are 3R, 2R1W, 2R1B, 1R2W, 1R2B, 1R1W1B, 2W1B, 1W2B, 3B
Therefore, there are 9 possible order of 3 balls drawn at a time.
b.) Here, I will assume you mean ‘at least 2 red balls and 1 blue ball’ if not there is only onw possible order of 4 balls drawn at a time with exactly 2 red balls and 1 blue ball. That is, 2R1W1B.
The possible order of 4 balls drawn at a time could be made with at least 2 red balls and 1 blue ball are 3R1B, 2R1W1B.
So, there are 2 possible order of 4 balls drawn at a time could be made with at least 2 red balls and 1 blue ball.