A coin is tossed 4 times. Find the probability that exactly 2 heads will appear.
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Let be a random variable representing the number of heads that appear in coin tosses, then the probability of success () is .
The probability that a binomial distributed variable with the number of tries, , and the probability of success, is equal to a value is given by .
Here, , so the probability that exactly two heads will appear () is given by
Therefore, the probability that exactly two heads will appear is 0.375.
The 4 stands for 4 tosses while the 2 stands for 2 outcomes(H,T)
Sample space=
Prob.(exactly two heads) =