The difference between $0.003286$ correct to three significant figures and $0.003286$ correct to four decimal places is

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godwin_ibrahimTyro

Asked: November 14, 20202020-11-14T22:50:04+00:00 2020-11-14T22:50:04+00:00In: Arithmetic, Numbers and Combinatorics

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Sengemegz · Accepted Answer · 2020-12-05T20:08:28+00:00

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Sengemegz Moderator

$0.003286=0.00329$ in 3 significant figure
$0.003286=0.0033$ in 4 decimal places
$\therefore 0.00329-0.0033=0.00001$

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