Area of square= $l^{2}=121cm^{2}$ $\therefore l= \sqrt{121}= 11cm$ Diagonal= $\sqrt{11^{2}+11^{2}}$ Diagonal= $\sqrt{121+121}$ Diagonal= $\sqrt{242}=15.56cm$

$(\dfrac{x}{y})^{m}=\dfrac{x^{m}}{y^{m}}$ The power of a quotient rule states that the power of a quotient is equal to the quotient obtained when the numerator and denominator are each raised to the indicated power separately, before the division is performed.

$\int 4x^{6}-2x^{3}+7x-4dx$ Integrating will give us $\dfrac{4x^{6+1}}{6+1}-\frac{2x^{3+1}}{3+1}+\frac{7x^{1+1}}{1+1}-4x+ c$ $\dfrac{4x^{7}}{7}-\frac{2x^{4}}{4}+\frac{7x^{2}}{2}-4x+c$ $\dfrac{4x^{7}}{7}-\frac{x^{4}}{2}+\frac{7x^{2}}{2}-4x+c$

$5x^{2}+10x-20=0$ Divide through by 5 $^{2}+2x-4=0$ Using formula method $a=1, b=2$ and $c=-4$ $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ $x=\frac{-2\pm \sqrt{2^{2}-4\times 1\times -4}}{2\times 1}$ $x=\frac{-2\pm \sqrt{4+16}}{2}$ $x=\frac{-2\pm \sqrt{20}}{2}$ $x=\frac{-2\pm 2\sqrt{5}}{2}$ $x=-1\pm \sqrt{Read more

$x^{2}+9x+20$ is a quadratic expression. This is because the highest power is two.